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(4x-6)^2-(2x-10(2x+1)-5(2x^2-1)=2(1-5x)^2
We move all terms to the left:
(4x-6)^2-(2x-10(2x+1)-5(2x^2-1)-(2(1-5x)^2)=0
We add all the numbers together, and all the variables
(4x-6)^2-(2x-10(2x+1)-5(2x^2-1)-(2(-5x+1)^2)=0
We calculate terms in parentheses: -(2x-10(2x+1)-5(2x^2-1)-(2(-5x+1)^2), so:
2x-10(2x+1)-5(2x^2-1)-(2(-5x+1)^2
We multiply parentheses
-10x^2+2x-20x-(2(-5x+1)^2-10+5
We add all the numbers together, and all the variables
-10x^2-18x-(2(-5x+1)^2-10+5
Back to the equation:
-(-10x^2-18x-(2(-5x+1)^2-10+5)
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